Fish, are you using a pitman arm type of sickle bar, or a belt drive? The belt drive models will allow you to lay the cutter bar down the backside of the dam while the tractor remains level across the top.
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1) And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1) Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT? PB answer: It depends.
