Good idea Scott, Drop me a # and I'll text him in the morning.
Jasonville is not too far from here, depending on what Bob says I'm sure I could shake free and meet you down there. Don't want you traveling out of your way, so I'll come to you if I get the OK.
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1) And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1) Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT? PB answer: It depends.
