Originally Posted By: John Wann
Great time spent with great people. Thanks Bob for taking this great group picture. Can't sink Bruce's dock.


Maybe not the dock, but the pontoon boat produced an anxious moment or two. wink

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.