Lucky dog! It is so dry here I am not sure a 4" rain would have any run off. The cracks in the ground are 2" wide and very deep.   I see I'm still in the exceptional category. Momma' always did say I was special.
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.
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