I think this photo emphasizes the importance of "it depends".

I've never found a HBG blueprint that definitively provided a correct identification in every case. Some see this photo and struggle to see HBG, yet I see nothing but HBG in it.

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.