Originally Posted By: Dave Davidson1
Matt's no stranger to some of us. He's a Fishery pro and a good one. Had a beer or 2 with him at PB1 in Arlington quite a while back.

Welcome back Matt.


Pretty good ice fisherman also.

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.