Tracy, I admire that philosophy. I will probably never be a proponent of trophy hunting, or at least what I perceive as being the most common form of trophy hunting, but your definition puts a different spin on things, and is food for thought.
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1) And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1) Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT? PB answer: It depends.
