HBG certainly will reproduce, but that's out of our control for the most part. Our job is to eliminate or severely curtail recruitment. Stay on top of your vegetation issues, and do not let it get out of hand. What else besides YP are in the pond?


"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.