While this leaves me as a man without a tribe somewhere in the middle, I discovered I don't need to identify with a group in order to possess an identity, either.
That's so deep I got the bends after reading it. Nice work, man.
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1) And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1) Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT? PB answer: It depends.
