I dug out the receipts for some stone we had spread on the drive a few weeks ago. Three tri-axle loads of 20.47, 19.73, and 19.85 tons respectively, for a cumulative total of exactly 60.05 tons of #4 stone.

The bill was $690 total, including stone, haul fees, and spreading.

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.