I think part of it comes down to the definition of "maintenance". If the road is regularly maintained, and the stone is fairly loose, then a blade works great. If it's been awhile, then I prefer the added weight of a box scraper that enables a bigger bite, and cutting depth.

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.