Jason you have some dandy fish, and I hope you continue to learn, and share what you learn. That's what I'm trying to do also. But as I cannot make you see where the error lies within your theory, I will simply wish you well, and bid you continued success.

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.