Fabulous fish Cecil! Three to three and a half inches down here today. Sketchy too. Fish tight to the bottom, reluctant to rise. Managed a few anyway.

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.