Originally Posted By: esshup
Even at that pace, the lake will be way short on cover for the fish. I'd look into using plastic wherever possible so you aren't fighting decomposing trees over the years.

For a "balanced" fishery, rough rule of thumb is 20% of the surface area is cover for fish.

Somebody check my math.

100 trees at 5' diameter = 6% of a surface acre?

π∙r2 is the area of the tree. 43,560 square feet in an acre.

Well, THAT didn't translate very well. pi times the radius squared should give the area of the 5' dia. christmas tree.

20% = 8,700 sq ft/acre


Engineers......they love the math! grin

C'mon Scott, admit it....sometimes you just gotta' wing it, seat-of-the-pants style, with no formulas! laugh


"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.