I've scrubbed off my share of rubber on tag axles and tight corners. Pushers aren't quite as bad in that respect.

Nine more feet of frame...I'm curious myself as to how the weight distribution works out.


"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.