I think this would make a great challenge...Bill writes the construction article, and a daring group of hardcore PB aficianados take it upon themselves to each build a boat, adding personal touches to customize it, and then post photos of the finished project. Bill could judge the winner.


"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.