"Inside this month's issue of Popular Mechanics.....
"Building the perfect pond boat....The Guppy"
"How flying cars will revolutionize commuting in the next 15 years"
" Part IV in our series on constructing the completely automated geodesic home of the future".............
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.
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