If I can help with anything Jammer, let me know. I don't have many answers, but I'm happy to stand, stare, and scratch my head right along with you. And, I know who to call. wink

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.