The boys wanted to tangle with something a little larger than our usual HBG, so we hit the catfish pond this afternoon...

Gavin, with a 6.5 lb CC:


Gage, with a 1.5 lb HSB....these were stocked a year ago at 6-7". This one went over 13" today.

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.