Originally Posted By: teehjaeh57
Originally Posted By: sprkplug
I've got a stick and a nice MIG, but I lust after a TIG.....


Hope your wife doesn't read your posts, Tony. Shame on you!



I know, I know......I'm weak! grin

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.