Originally Posted By: Bruce Condello
Pond Boss is the coffee shop where pond experts gather to share their knowledge.


I'm no pond expert, but could I get a slice of pie with my coffee and just listen in from a nearby table? grin

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.