I had about 2" right offshore, with an inch of that being good ice, and the rest junk. Out in deeper water, I had an inch of junk on top of 2.5" of good clear ice...probably could've walked it, but I fish alone so I stayed in the jonboat....may be braver today.

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.