One of my son's seventh grade classmates has already had Christmas this week....her mother believes that the 25th will never arrive. Apparently, today is the last day she's coming to school also, as mom wants to spend as much time as possible with her, before the end arrives....

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.