Aww man, don't rub it in.... My gear's ready, new auger, nice selection of new tungsten jigs.... no ice, and the prospect for any in the immediate future is slim.... 60 degrees this past Saturday
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1) And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1) Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT? PB answer: It depends.
