Originally Posted By: 2trackin
Anyone have any input as to how much well water I'd need to pump to impact the pond temp?
Not sure if my methodology is technically correct, but logic suggests that 10k gal of 68F water added to 1-ac/ft (325,800 gal) of 85F water will produce a combined temperature of 84.5F (a .5 degree reduction to the larger water-volume).

Four variables impact the final value, and assumes instantaneous blending of both volumes and their relative temps. Plus, the initial change may be short-lived due to the ambient air-temp and other variables that affect heat induction or dissipation.

325,800 x .0085 = 2,769
10,000 x .0068 = 68
Total of the two volumes: 335,800 gal
Total thermal units: 2,837

2,837
335,800 = .00845 (= 84.5F)


Kelly Duffie
Cypress, TX