You're right about that, George..
Every time I get interested in something new, I tend to totally immerse myself in it to the point of near fanaticism...
I'll try to slow down and not over-complicate it so much!!
Thanks again for your help!
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.
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