Remember also that this is Pondboss, and we strive to over complicate, over think, and over do. So while I don't care who the models are, I expect their dainty feet to be clad in Louis Vuitton, only.
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1) And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1) Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT? PB answer: It depends.
