Hi, my name's Tony, just found the site, looks great!

I think I will be right at home here, matter of fact it feels like I've been here already! That's all for now, got a terrible headache.

Oh, and I like HBG.


"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.