Hi, my name's Tony, just found the site, looks great!
I think I will be right at home here, matter of fact it feels like I've been here already! That's all for now, got a terrible headache.
Oh, and I like HBG.
"Forget pounds and ounces, I'm figuring displacement!"
If we accept that: MBG(+)FGSF(=)HBG(F1) And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1) Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT? PB answer: It depends.