Originally Posted By: RAH
You need to come north some time and share a beer with me on my dock. Just don't let my wife hear us "discussing" things at the top of our lungs. She gives me grief over that!


Thanks RAH. No worries.


"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.