Originally Posted By: Pat Williamson
Originally Posted By: TGW1
Sorry if I offended anyone here as I am on a rant today lol

Tracy

Tracy sometimes it's good to air it out. Nothing changes unless you fuss.... The squeaky wheel gets the grease......


Or swapped out for a new one.... grin wink

"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.