Scott, (esshup) paid me a visit today and we spent an enjoyable afternoon tinkering on chainsaws, talking about ponds, pondering the peculiar nature of man, picking up equipment on backroads, and yes, even did a little fishing.

As is often the case when you decree your fish should be on their best behavior, they decided instead to sulk and languish in the depths, all the while mocking our offerings. We caught some good fish, but no big fish answered the call.

Esshup did graciously assist me in my quest to eliminate the bigger LMB from the HBG pond, however.


"Forget pounds and ounces, I'm figuring displacement!"

If we accept that: MBG(+)FGSF(=)HBG(F1)
And we surmise that: BG(>)HBG(F1) while GSF(<)HBG(F1)
Would it hold true that: HBG(F1)(+)AM500(x)q.d.(=)1.5lbGRWT?
PB answer: It depends.